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7m^2-63m+98=0
a = 7; b = -63; c = +98;
Δ = b2-4ac
Δ = -632-4·7·98
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-35}{2*7}=\frac{28}{14} =2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+35}{2*7}=\frac{98}{14} =7 $
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